(y^2+5y+4)*(3y+2)=0

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Solution for (y^2+5y+4)*(3y+2)=0 equation: 


Simplifying
(y2 + 5y + 4)(3y + 2) = 0

Reorder the terms:
(4 + 5y + y2)(3y + 2) = 0

Reorder the terms:
(4 + 5y + y2)(2 + 3y) = 0

Multiply (4 + 5y + y2) * (2 + 3y)
(4(2 + 3y) + 5y * (2 + 3y) + y2(2 + 3y)) = 0
((2 * 4 + 3y * 4) + 5y * (2 + 3y) + y2(2 + 3y)) = 0
((8 + 12y) + 5y * (2 + 3y) + y2(2 + 3y)) = 0
(8 + 12y + (2 * 5y + 3y * 5y) + y2(2 + 3y)) = 0
(8 + 12y + (10y + 15y2) + y2(2 + 3y)) = 0
(8 + 12y + 10y + 15y2 + (2 * y2 + 3y * y2)) = 0
(8 + 12y + 10y + 15y2 + (2y2 + 3y3)) = 0

Combine like terms: 12y + 10y = 22y
(8 + 22y + 15y2 + 2y2 + 3y3) = 0

Combine like terms: 15y2 + 2y2 = 17y2
(8 + 22y + 17y2 + 3y3) = 0

Solving
8 + 22y + 17y2 + 3y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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